• Skip to primary navigation
  • Skip to main content
A-Level H2 Chemistry Tuition by 10 Year Series Author

A-Level H2 Chemistry Tuition by 10 Year Series Author

Advanced Chemistry Made Easy

  • A Level H2 Chemistry Tuition
  • Success Stories
  • Books
    • A-Level H2 Chemistry Topical Edition Past Year Series
    • A-Level H2 Chemistry Yearly Edition Past Year Series
  • Videos
  • About Me
  • Contact

Chemistry Questions

Ideal Gas Law: Exam-Based Question

February 27, 2012 By Sean Chua Leave a Comment

In the previous blog post, we have discussed on the The Gaseous State for A-Level H2 Chemistry and the meaning of Ideal Gas (versus a Real Gas).

We have also discussed on Ideal Gas Equation and how to apply it on exam-based question.

Today, we shall look at another common exam-based question that has been seen modified versions in many Junior Colleges (JC) and Institutes in Singapore.

Question:

At 338K, pure PCl5 gas present in a flask has a pressure of 25.5 kPa. At 480K, the gas is completely dissociated into PCl3(g) and Cl2(g).  What is the pressure in the flask at 48oK?

Suggested Answer:

From the Ideal Gas Equation of PV = nRT,

we have P = (nRT)/V

Since V and R are constants,

we have (n1T1)/P1 = (n2T2)/P2

The next step is to write a balanced chemical equation to show the dissociate of PCl5 gas at 480K, which is:

PCl5(g) –> PCl3(g) + Cl2(g)

As such, the number of moles of gases has doubled at 480K since 1 mol of PCl5 has dissociated to produce 2 moles of gases (i.e. 1 mol of PCl3 and 1 mol of Cl2).

Thus, ratio of n2:n1 is 2:1

From (n1T1)/P1 = (n2T2)/P2,

we have P2 = (n2T2)(P1)/(n1T1) = (2 x 480)(25.5)/(1 x 338) = 72.4 kPa

Hope you have learned something useful today. Feel free to share it with your friends.

Keep Learning, Keep Clarifying, Keep Sharing!

  • « Go to Previous Page
  • Page 1
  • Page 2
  • Page 3
  • Page 4
  • Page 5
  • Page 6
  • Interim pages omitted …
  • Page 18
  • Go to Next Page »

Copyright © 2010–2026 · ALevelH2Chemistry.com · Talk to us at 88290998